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- remove unnecessary ";"
- use std::tie for lexicographical ordering
- simplify loop condition
The offset always has step +1 on each iteration, so it would just hit one of the two boundary anyway
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| .. | ||
| audio_core | ||
| citra | ||
| citra_qt | ||
| common | ||
| core | ||
| dedicated_room | ||
| input_common | ||
| network | ||
| tests | ||
| video_core | ||
| web_service | ||
| .clang-format | ||
| CMakeLists.txt | ||